Pattern For Q(x)=(x+1)(x−1)2Q(x)=(x+1)(x-1)^2Q(x)=(x+1)(x−1)2: P(x)(x+1)(x−1)2=Ax+1+Bx−1+C(x−1)2\frac{P(x)}{(x+1)(x-1)^2}=\frac{A}{x+1}+\frac{B}{x-1}+\frac{C}{(x-1)^2}(x+1)(x−1)2P(x)=x+1A+x−1B+(x−1)2C