Case: (x−a)(x2+px+q)(x-a)(x^2+px+q)(x−a)(x2+px+q) If x2+px+qx^2+px+qx2+px+q is irreducible, use: P(x)(x−a)(x2+px+q)=Ax−a+Bx+Cx2+px+q\frac{P(x)}{(x-a)(x^2+px+q)}=\frac{A}{x-a}+\frac{Bx+C}{x^2+px+q}(x−a)(x2+px+q)P(x)=x−aA+x2+px+qBx+C