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11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=4x+7f(x)=4x+7f(x)=4x+7menu_book•(ii)f(x)=sin⁡xf(x)=\sin xf(x)=sinxmenu_book•(iii)f(x)=x2+x2−1f(x)=x^2+x^2-1f(x)=x2+x2−1menu_book•(iv)f(x)=tan⁡xf(x)=\tan xf(x)=tanx
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school

11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=4x+7f(x)=4x+7f(x)=4x+7menu_book•(ii)f(x)=sin⁡xf(x)=\sin xf(x)=sinxmenu_book•(iii)f(x)=x2+x2−1f(x)=x^2+x^2-1f(x)=x2+x2−1menu_book•(iv)f(x)=tan⁡xf(x)=\tan xf(x)=tanx
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Accedmychevron_right11thchevron_rightmathchevron_rightFunctions And Graphschevron_rightExercise 2.1

(iv)

tan⁡(a+h)−tan⁡ah=sin⁡hhcos⁡(a+h)cos⁡a\boxed{\frac{\tan(a+h)-\tan a}{h}=\frac{\sin h}{h\cos(a+h)\cos a}}htan(a+h)−tana​=hcos(a+h)cosasinh​​
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(iv)