Solution
Given .
(i) Domain and range
A linear function is defined for all real and produces all real values.
(ii) One-to-one
Assume :
So is one-to-one.
(iii) Onto (co-domain )
Let . Solve :
Since , every real has a preimage, so is onto.
Given .
A linear function is defined for all real and produces all real values.
Assume :
So is one-to-one.
Let . Solve :
Since , every real has a preimage, so is onto.