Accedmychevron_right11thchevron_rightmathchevron_rightFunctions And Graphschevron_rightExercise 2.2

Solution

For intercepts:

  • xx-intercept: set y=0y=0.
  • yy-intercept: set x=0x=0.

(i) y=5x+10y=-5x+10

y=05x+10=0x=2(2,0)x=0y=10(0,10)\begin{aligned} y=0&\Rightarrow -5x+10=0\Rightarrow x=2\quad\Rightarrow (2,0)\\ x=0&\Rightarrow y=10\quad\Rightarrow (0,10) \end{aligned} x-int (2,0),  y-int (0,10)\boxed{\text{$x$-int }(2,0),\;\text{$y$-int }(0,10)}

(ii) y=2x1y=2x-1

y=02x1=0x=12(12,0)x=0y=1(0,1)\begin{aligned} y=0&\Rightarrow 2x-1=0\Rightarrow x=\frac{1}{2}\quad\Rightarrow \left(\frac{1}{2},0\right)\\ x=0&\Rightarrow y=-1\quad\Rightarrow (0,-1) \end{aligned} x-int (12,0),  y-int (0,1)\boxed{\text{$x$-int }\left(\frac{1}{2},0\right),\;\text{$y$-int }(0,-1)}

(iii) y=12x3y=\dfrac{1}{2}x-3

y=012x3=0x=6(6,0)x=0y=3(0,3)\begin{aligned} y=0&\Rightarrow \frac{1}{2}x-3=0\Rightarrow x=6\quad\Rightarrow (6,0)\\ x=0&\Rightarrow y=-3\quad\Rightarrow (0,-3) \end{aligned} x-int (6,0),  y-int (0,3)\boxed{\text{$x$-int }(6,0),\;\text{$y$-int }(0,-3)}

(iv) y=3x+32y=3x+\dfrac{3}{2}

y=03x+32=03x=32x=12(12,0)x=0y=32(0,32)\begin{aligned} y=0&\Rightarrow 3x+\frac{3}{2}=0\Rightarrow 3x=-\frac{3}{{2}}\Rightarrow x=-\frac{1}{2}\quad\Rightarrow \left(-\frac{1}{2},0\right)\\ x=0&\Rightarrow y=\frac{3}{2}\quad\Rightarrow \left(0,\frac{3}{2}\right) \end{aligned} x-int (12,0),  y-int (0,32)\boxed{\text{$x$-int }\left(-\frac{1}{2},0\right),\;\text{$y$-int }\left(0,\frac{3}{2}\right)}