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11TH · MATH

Question 3

menu_bookSolutionmenu_bookTheorymenu_book•(i)(AB)C=A(BC)(AB)C=A(BC)(AB)C=A(BC)menu_book•(ii)A(B+C)=AB+ACA(B+C)=AB+ACA(B+C)=AB+AC
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11TH · MATH

Question 3

menu_bookSolutionmenu_bookTheorymenu_book•(i)(AB)C=A(BC)(AB)C=A(BC)(AB)C=A(BC)menu_book•(ii)A(B+C)=AB+ACA(B+C)=AB+ACA(B+C)=AB+AC
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Accedmychevron_right11thchevron_rightmathchevron_rightMatrices And Determinantschevron_rightExercise 4.1

(i)

(AB)C=A(BC)\boxed{(AB)C=A(BC)}(AB)C=A(BC)​
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(ii)
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(i)