Accedmychevron_right11thchevron_rightmathchevron_rightMatrices And Determinantschevron_rightExercise 4.2

Solution

Let AA be a 3×33\times 3 matrix.

Then kAkA is obtained by multiplying every entry (equivalently every row) of AA by kk.

A basic determinant property is:

  • If one row of a determinant is multiplied by kk, the determinant is multiplied by kk.

Since kAkA has each of the 3 rows multiplied by kk, we get:

kA=kkkA=k3A|kA|=k\cdot k\cdot k\,|A|=k^3|A| kA=k3A\boxed{|kA|=k^3|A|}