Accedmychevron_right11thchevron_rightmathchevron_rightPartial Fractionschevron_rightExercise 5.1

Solution

Let:

3x212x+11(x1)(x2)(x3)=Ax1+Bx2+Cx3\frac{3x^2-12x+11}{(x-1)(x-2)(x-3)} =\frac{A}{x-1}+\frac{B}{x-2}+\frac{C}{x-3}

Solving gives A=1A=1, B=1B=1, C=1C=1.

3x212x+11(x1)(x2)(x3)=1x1+1x2+1x3\boxed{\frac{3x^2-12x+11}{(x-1)(x-2)(x-3)}=\frac{1}{x-1}+\frac{1}{x-2}+\frac{1}{x-3}}