schoolAccedmy
9th10th
11th12th
school

11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)nP3=504{}^nP_3 = 504nP3​=504menu_book•(ii)15Pn=15⋅14⋅13⋅12⋅11{}^{15}P_n = 15 \cdot 14 \cdot 13 \cdot 12 \cdot 1115Pn​=15⋅14⋅13⋅12⋅11menu_book•(iii)nP5:n−2P2=540:1{}^nP_5 : {}^{n-2}P_2 = 540 : 1nP5​:n−2P2​=540:1
arrow_backBack
school

11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)nP3=504{}^nP_3 = 504nP3​=504menu_book•(ii)15Pn=15⋅14⋅13⋅12⋅11{}^{15}P_n = 15 \cdot 14 \cdot 13 \cdot 12 \cdot 1115Pn​=15⋅14⋅13⋅12⋅11menu_book•(iii)nP5:n−2P2=540:1{}^nP_5 : {}^{n-2}P_2 = 540 : 1nP5​:n−2P2​=540:1
arrow_backBack
Accedmychevron_right11thchevron_rightmathchevron_rightPermutations And Combinationschevron_rightExercise 7.2

(i) ( n=9 ); (ii) ( n=5 ); (iii) ( n=10 ).

Answer: 9; 5; 10

arrow_back
Previous Question
Question 1
Next Question
Question 3
arrow_forward
On this page
No headings yet