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11TH · MATH

Question 7

menu_bookSolutionmenu_bookTheorymenu_book•(i)a−b, b−c, c−da - b,\ b - c,\ c - da−b, b−c, c−dare in G.P.menu_book•(ii)a2−b2, b2−c2, c2−d2a^2 - b^2,\ b^2 - c^2,\ c^2 - d^2a2−b2, b2−c2, c2−d2are in G.P.menu_book•(iii)a2+b2, b2+c2, c2+d2a^2 + b^2,\ b^2 + c^2,\ c^2 + d^2a2+b2, b2+c2, c2+d2are in G.P.
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11TH · MATH

Question 7

menu_bookSolutionmenu_bookTheorymenu_book•(i)a−b, b−c, c−da - b,\ b - c,\ c - da−b, b−c, c−dare in G.P.menu_book•(ii)a2−b2, b2−c2, c2−d2a^2 - b^2,\ b^2 - c^2,\ c^2 - d^2a2−b2, b2−c2, c2−d2are in G.P.menu_book•(iii)a2+b2, b2+c2, c2+d2a^2 + b^2,\ b^2 + c^2,\ c^2 + d^2a2+b2, b2+c2, c2+d2are in G.P.
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Accedmychevron_right11thchevron_rightmathchevron_rightSequences And Serieschevron_rightExercise 6.5

(a,b,c,d) in G.P. ⇒ (b=ar,\ c=ar^2,\ d=ar^3)

(i)

[ a-b=a(1-r),\quad b-c=ar(1-r),\quad c-d=ar^2(1-r) ] Clearly in G.P. with ratio (r).

(ii)

[ a^2-b^2=(a-b)(a+b),\quad b^2-c^2=(b-c)(b+c),\quad c^2-d^2=(c-d)(c+d) ] Using (b^2=ac) etc., the ratios are equal.

(iii) Similar verification using (b^2=ac), (c^2=bd).

Proved.

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(i)(ii)(iii) Similar verification using \(b^2=ac\), \(c^2=bd\).