A.M. exceeds G.M. by 2, sum = 20.

Let numbers be (x,y>0). [ \dfrac{x+y}{2}-\sqrt{xy}=2,\quad x+y=20 ] [ 10-\sqrt{xy}=2\implies\sqrt{xy}=8\implies xy=64 ]

[ t^2-20t+64=0\implies(t-16)(t-4)=0 ]

Answer: 4 and 16