Solution
Given:
d(s)=0.02s2+0.1s
Safe braking means:
0.02s2+0.1s≤50
Multiply by 100:
2s2+10s≤5000
Divide by 2:
s2+5s−2500≤0
Solve s2+5s−2500=0:
s=2−5±25+10000=2−5±10025=2−5±5401
Only the positive root is physically meaningful:
s=25(401−1)≈47.56
Since the parabola opens upward, the inequality ≤0 holds between the roots. With s≥0:
0≤s≤25(401−1) km/h
0≤s≲47.56 km/h