Accedmychevron_right11thchevron_rightmathchevron_rightTheory Of Quadratic Functionschevron_rightExercise 3.2

Solution

Given:

d(s)=0.02s2+0.1sd(s)=0.02s^2+0.1s

Safe braking means:

0.02s2+0.1s500.02s^2+0.1s\le 50

Multiply by 100:

2s2+10s50002s^2+10s\le 5000

Divide by 2:

s2+5s25000s^2+5s-2500\le 0

Solve s2+5s2500=0s^2+5s-2500=0:

s=5±25+100002=5±100252=5±54012\begin{aligned} s&=\frac{-5\pm\sqrt{25+10000}}{2}\\ &=\frac{-5\pm\sqrt{10025}}{2}\\ &=\frac{-5\pm 5\sqrt{401}}{2} \end{aligned}

Only the positive root is physically meaningful:

s=5(4011)247.56 s=\frac{5(\sqrt{401}-1)}{2}\approx 47.56

Since the parabola opens upward, the inequality 0\le 0 holds between the roots. With s0s\ge 0:

0s5(4011)2 km/h\boxed{0\le s\le \frac{5(\sqrt{401}-1)}{2}}\ \text{km/h} 0s47.56 km/h\boxed{0\le s\lesssim 47.56\ \text{km/h}}