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11TH · MATH

Question 6

menu_bookSolutionmenu_bookTheorymenu_book•(i)sin⁡(α+β)=sin⁡γ\sin(\alpha + \beta) = \sin\gammasin(α+β)=sinγmenu_book•(ii)sec⁡(α+β2)=csc⁡γ2\sec\left(\dfrac{\alpha + \beta}{2}\right) = \operatorname{csc}\dfrac{\gamma}{2}sec(2α+β​)=csc2γ​menu_book•(iii)cosec⁡α=1sin⁡(β+γ)\operatorname{cosec}\alpha = \dfrac{1}{\sin(\beta + \gamma)}cosecα=sin(β+γ)1​menu_book•(iv)tan⁡(α+β)+tan⁡γ=0\tan(\alpha + \beta) + \tan\gamma = 0tan(α+β)+tanγ=0
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11TH · MATH

Question 6

menu_bookSolutionmenu_bookTheorymenu_book•(i)sin⁡(α+β)=sin⁡γ\sin(\alpha + \beta) = \sin\gammasin(α+β)=sinγmenu_book•(ii)sec⁡(α+β2)=csc⁡γ2\sec\left(\dfrac{\alpha + \beta}{2}\right) = \operatorname{csc}\dfrac{\gamma}{2}sec(2α+β​)=csc2γ​menu_book•(iii)cosec⁡α=1sin⁡(β+γ)\operatorname{cosec}\alpha = \dfrac{1}{\sin(\beta + \gamma)}cosecα=sin(β+γ)1​menu_book•(iv)tan⁡(α+β)+tan⁡γ=0\tan(\alpha + \beta) + \tan\gamma = 0tan(α+β)+tanγ=0
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