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11TH · MATH

Question 5

menu_bookSolutionmenu_bookTheorymenu_book•(i)u=αi+3j+k\mathbf{u} = \alpha\mathbf{i} + 3\mathbf{j} + \mathbf{k}u=αi+3j+k, $\mathbf{v} = \mathbf{i} - 2\mathbf{j} + \alpha\mathbf{k}$menu_book•(ii)u=αi+2αj−k\mathbf{u} = \alpha\mathbf{i} + 2\alpha\mathbf{j} - \mathbf{k}u=αi+2αj−k, $\mathbf{v} = \mathbf{i} + \alpha\mathbf{j} + 3\mathbf{k}$
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11TH · MATH

Question 5

menu_bookSolutionmenu_bookTheorymenu_book•(i)u=αi+3j+k\mathbf{u} = \alpha\mathbf{i} + 3\mathbf{j} + \mathbf{k}u=αi+3j+k, $\mathbf{v} = \mathbf{i} - 2\mathbf{j} + \alpha\mathbf{k}$menu_book•(ii)u=αi+2αj−k\mathbf{u} = \alpha\mathbf{i} + 2\alpha\mathbf{j} - \mathbf{k}u=αi+2αj−k, $\mathbf{v} = \mathbf{i} + \alpha\mathbf{j} + 3\mathbf{k}$
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