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11TH · MATH

Question 6

menu_bookSolutionmenu_bookTheorymenu_book•(i)u=5i−j+k;v=j−5k;w=−15i+3j−3k\mathbf{u} = 5\mathbf{i} - \mathbf{j} + \mathbf{k}; \mathbf{v} = \mathbf{j} - 5\mathbf{k}; \mathbf{w} = -15\mathbf{i} + 3\mathbf{j} - 3\mathbf{k}u=5i−j+k;v=j−5k;w=−15i+3j−3kmenu_book•(ii)u=i+2j−k;v=−i+j+k;w=−π2i−πj+π2k\mathbf{u} = \mathbf{i} + 2\mathbf{j} - \mathbf{k}; \mathbf{v} = -\mathbf{i} + \mathbf{j} + \mathbf{k}; \mathbf{w} = -\dfrac{\pi}{2}\mathbf{i} - \pi\mathbf{j} + \dfrac{\pi}{2}\mathbf{k}u=i+2j−k;v=−i+j+k;w=−2π​i−πj+2π​k
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11TH · MATH

Question 6

menu_bookSolutionmenu_bookTheorymenu_book•(i)u=5i−j+k;v=j−5k;w=−15i+3j−3k\mathbf{u} = 5\mathbf{i} - \mathbf{j} + \mathbf{k}; \mathbf{v} = \mathbf{j} - 5\mathbf{k}; \mathbf{w} = -15\mathbf{i} + 3\mathbf{j} - 3\mathbf{k}u=5i−j+k;v=j−5k;w=−15i+3j−3kmenu_book•(ii)u=i+2j−k;v=−i+j+k;w=−π2i−πj+π2k\mathbf{u} = \mathbf{i} + 2\mathbf{j} - \mathbf{k}; \mathbf{v} = -\mathbf{i} + \mathbf{j} + \mathbf{k}; \mathbf{w} = -\dfrac{\pi}{2}\mathbf{i} - \pi\mathbf{j} + \dfrac{\pi}{2}\mathbf{k}u=i+2j−k;v=−i+j+k;w=−2π​i−πj+2π​k
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