QuestionsQuestion 1Find the real values of xxx and yyy in each of the following:(i)x+iy+2−3i=i(5−i)(3+4i)x+iy+2-3i=i(5-i)(3+4i)x+iy+2−3i=i(5−i)(3+4i)(ii)(x+iy)(1−i)=(2−3i)(−5+5i)−35i(x+iy)(1-i)=(2-3i)(-5+5i)-\dfrac{3}{5}i(x+iy)(1−i)=(2−3i)(−5+5i)−53i(iii)x2+i+y3−i=4+5i\dfrac{x}{2+i}+\dfrac{y}{3-i}=4+5i2+ix+3−iy=4+5iSolutionTheoryQuestion 2If z1=−13+24iz_1=-13+24iz1=−13+24i and z2=x+yiz_2=x+yiz2=x+yi, find the real values of xxx and yyy such that z1−z2=−27+15iz_1-z_2=-27+15iz1−z2=−27+15i.SolutionTheoryQuestion 3Find the real values of xxx and yyy if:(i)(x+iy)2=25+60i(x+iy)^2=25+60i(x+iy)2=25+60i(ii)(x+iy)2=64+48i(x+iy)^2=64+48i(x+iy)2=64+48i(iii)(x+iy)2=2i−33+i(x+iy)^2=\dfrac{2i-3}{3+i}(x+iy)2=3+i2i−3SolutionTheoryQuestion 4If z1=2+3iz_1=2+3iz1=2+3i and z2=1−aiz_2=1-aiz2=1−ai, find the real value of aaa such that Im(z1z2)=7\operatorname{Im}(z_1z_2)=7Im(z1z2)=7.SolutionTheoryQuestion 5If z1=x+yiz_1=x+yiz1=x+yi and z2=a+biz_2=a+biz2=a+bi, find x,y,a,bx,y,a,bx,y,a,b such that z1+z2=10+4iz_1+z_2=10+4iz1+z2=10+4i and z1−z2=6+2iz_1-z_2=6+2iz1−z2=6+2i.SolutionTheoryQuestion 6Show that for all z1,z2∈Cz_1,z_2\in\mathbb{C}z1,z2∈C, z1z2‾=z1ˉ z2ˉ\overline{z_1z_2}=\bar{z_1}\,\bar{z_2}z1z2=z1ˉz2ˉ.SolutionTheoryQuestion 7Find the square root of the following complex numbers:(i)−7−24i-7-24i−7−24i(ii)8−6i8-6i8−6i(iii)−15−36i-15-36i−15−36i(iv)119+120i119+120i119+120iSolutionTheoryQuestion 8Find the square root of 13−203i13-20\sqrt{3}i13−203i and represent it on an Argand diagram.SolutionTheoryQuestion 9Find the real values of xxx and yyy if (−7+i)(x+yi)+(−1−5i)=i(11−i)(-7+i)(x+yi)+(-1-5i)=i(11-i)(−7+i)(x+yi)+(−1−5i)=i(11−i).SolutionTheoryQuestion 10Find the real values of xxx and yyy if (5−2i)(x+yi)+3=i(11−i)−4i(5-2i)(x+yi)+3=i(11-i)-4i(5−2i)(x+yi)+3=i(11−i)−4i.SolutionTheoryQuestion 11Find the real values of uuu and vvv if u2+v22+i=v−32−i=4i\dfrac{u^2+v^2}{2+i}=\dfrac{v-3}{2-i}=4i2+iu2+v2=2−iv−3=4i.SolutionTheoryQuestion 12If z1=4+5iz_1=4+5iz1=4+5i and z2=a−2iz_2=a-2iz2=a−2i, find the real values of aaa such that Re(z1z2)=20\operatorname{Re}(z_1z_2)=20Re(z1z2)=20.SolutionTheory