QuestionsQuestion 1Plot the following points:(i)(2,75∘)(2, 75^\circ)(2,75∘)(ii)(−3,120∘)(-3, 120^\circ)(−3,120∘)(iii)(2,π6)(2, \dfrac{\pi}{6})(2,6π)(iv)(5,5π6)(5, \dfrac{5\pi}{6})(5,65π)(v)(−52,π3)(-\dfrac{5}{2}, \dfrac{\pi}{3})(−25,3π)(vi)(−3,−2π3)(-3, -\dfrac{2\pi}{3})(−3,−32π)(vii)(92,19π12)(\dfrac{9}{2}, \dfrac{19\pi}{12})(29,1219π)(viii)(−52,5π12)(-\dfrac{5}{2}, \dfrac{5\pi}{12})(−25,125π)SolutionTheoryQuestion 2Express the following complex numbers in polar form:(i)4+3i4+3i4+3i(ii)1+i1+i1+i(iii)12+32i\dfrac{1}{2}+\dfrac{\sqrt{3}}{2}i21+23i(iv)−52−532i-\dfrac{5}{2}-\dfrac{5\sqrt{3}}{2}i−25−253i(v)1−i1+i\dfrac{1-i}{1+i}1+i1−i(vi)3+i1+3i\dfrac{\sqrt{3}+i}{1+\sqrt{3}i}1+3i3+i(vii)3+4i4+3i\dfrac{3+4i}{4+3i}4+3i3+4i(viii)32+32i\dfrac{3}{2}+\dfrac{\sqrt{3}}{2}i23+23iSolutionTheoryQuestion 3Convert each of the complex numbers zzz in the rectangular form x+iyx+iyx+iy:(i)4(cos5π3+isin5π3)4\left(\cos\dfrac{5\pi}{3}+i\sin\dfrac{5\pi}{3}\right)4(cos35π+isin35π)(ii)32(cos7π6+isin7π6)\dfrac{3}{2}\left(\cos\dfrac{7\pi}{6}+i\sin\dfrac{7\pi}{6}\right)23(cos67π+isin67π)(iii)∣z∣=7,arg(z)=23π12|z|=7,\arg(z)=\dfrac{23\pi}{12}∣z∣=7,arg(z)=1223π(iv)∣z∣=11,arg(z)=−11π12|z|=11,\arg(z)=-\dfrac{11\pi}{12}∣z∣=11,arg(z)=−1211π(v)∣z∣=103,arg(z)=−17π12|z|=\dfrac{10}{3},\arg(z)=-\dfrac{17\pi}{12}∣z∣=310,arg(z)=−1217π(vi)2cos(−33∘)+i 2sin(−33∘)2\cos(-33^\circ)+i\,2\sin(-33^\circ)2cos(−33∘)+i2sin(−33∘)SolutionTheoryQuestion 4If z1=9(cos5π4+isin5π4)z_1=9\left(\cos\dfrac{5\pi}{4}+i\sin\dfrac{5\pi}{4}\right)z1=9(cos45π+isin45π) and z2=5(cosπ3+isinπ3)z_2=5\left(\cos\dfrac{\pi}{3}+i\sin\dfrac{\pi}{3}\right)z2=5(cos3π+isin3π) then find:(i)z1+z2z_1+z_2z1+z2(ii)z1−z2z_1-z_2z1−z2(iii)z1⋅z2z_1\cdot z_2z1⋅z2(iv)z1z2\dfrac{z_1}{z_2}z2z1SolutionTheoryQuestion 5If z1=7(cos23π12+isin23π12)z_1=7\left(\cos\dfrac{23\pi}{12}+i\sin\dfrac{23\pi}{12}\right)z1=7(cos1223π+isin1223π) and z2=11(cos11π12+isin11π12)z_2=11\left(\cos\dfrac{11\pi}{12}+i\sin\dfrac{11\pi}{12}\right)z2=11(cos1211π+isin1211π) then find the following and express the result into x+iyx+iyx+iy form:(i)z1+z2z_1+z_2z1+z2(ii)z1−z2z_1-z_2z1−z2(iii)z1⋅z2z_1\cdot z_2z1⋅z2(iv)z1z2\dfrac{z_1}{z_2}z2z1SolutionTheoryQuestion 6If z1z_1z1 and z2z_2z2 are two complex numbers, show that:(i)Arg(z1z2)=Arg(z1)+Arg(z2)\operatorname{Arg}(z_1z_2)=\operatorname{Arg}(z_1)+\operatorname{Arg}(z_2)Arg(z1z2)=Arg(z1)+Arg(z2)(ii)Arg(z1z2)=Arg(z1)−Arg(z2)\operatorname{Arg}\left(\dfrac{z_1}{z_2}\right)=\operatorname{Arg}(z_1)-\operatorname{Arg}(z_2)Arg(z2z1)=Arg(z1)−Arg(z2)SolutionTheoryQuestion 7Divide z1=6(cos150∘+isin150∘)z_1=6(\cos 150^\circ+i\sin 150^\circ)z1=6(cos150∘+isin150∘) by z2=3(cos30∘+isin30∘)z_2=3(\cos 30^\circ+i\sin 30^\circ)z2=3(cos30∘+isin30∘) and express in x+iyx+iyx+iy form.SolutionTheoryQuestion 8Multiply z1=2(cos60∘+isin60∘)z_1=2(\cos 60^\circ+i\sin 60^\circ)z1=2(cos60∘+isin60∘) and z2=5(cos90∘+isin90∘)z_2=5(\cos 90^\circ+i\sin 90^\circ)z2=5(cos90∘+isin90∘) and express in x+iyx+iyx+iy form.SolutionTheoryQuestion 9Find the modulus and argument of z=−2−2iz=-2-2iz=−2−2i.SolutionTheoryQuestion 10Write the equation Arg(z−2+i−2−2i)=2π3\operatorname{Arg}\left(\dfrac{z-2+i}{-2-2i}\right)=\dfrac{2\pi}{3}Arg(−2−2iz−2+i)=32π in cartesian form, if z=x+iyz=x+iyz=x+iy.SolutionTheoryQuestion 11If z=x+iyz=x+iyz=x+iy and arg(z−1+2iz+1−2i)=9π4\arg\left(\dfrac{z-1+2i}{z+1-2i}\right)=\dfrac{9\pi}{4}arg(z+1−2iz−1+2i)=49π, show that x2+y2+4x+2y−5=0x^2+y^2+4x+2y-5=0x2+y2+4x+2y−5=0.SolutionTheoryQuestion 12If z=x+iyz=x+iyz=x+iy and arg(z−2−3i)−arg(z+2+3i)=2π\arg(z-2-3i)-\arg(z+2+3i)=2\piarg(z−2−3i)−arg(z+2+3i)=2π, show that 2y=3x2y=3x2y=3x.SolutionTheoryQuestion 13Solve the equation ∣z−2∣=∣z+2∣|z-2|=|z+2|∣z−2∣=∣z+2∣ for z=x+iyz=x+iyz=x+iy.SolutionTheoryQuestion 14For z=x+iyz=x+iyz=x+iy, solve the equation ∣5z+4+i∣=∣5z−3+2i∣|5z+4+i|=|5z-3+2i|∣5z+4+i∣=∣5z−3+2i∣.SolutionTheoryQuestion 15Determine the set of points z=x+iyz=x+iyz=x+iy that satisfy ∣3z−2+i∣=∣3z+i∣|3z-2+i|=|3z+i|∣3z−2+i∣=∣3z+i∣.SolutionTheoryQuestion 16If z=x+iyz=x+iyz=x+iy and w=1−izz−iw=\dfrac{1-iz}{z-i}w=z−i1−iz, show that ∣w∣=1⇒z|w|=1 \Rightarrow z∣w∣=1⇒z is real.SolutionTheoryQuestion 17If z1z_1z1 and z2z_2z2 are different complex numbers with ∣z2∣=1|z_2|=1∣z2∣=1, find ∣z2−z11−z1z2∣\left|\dfrac{z_2-z_1}{1-z_1z_2}\right|1−z1z2z2−z1.SolutionTheoryQuestion 18An AC source supplies a voltage V=120(cosπ4+isinπ4)V=120\left(\cos\dfrac{\pi}{4}+i\sin\dfrac{\pi}{4}\right)V=120(cos4π+isin4π) volts to a circuit with impedance Z=1+i32Z=\dfrac{1+i\sqrt{3}}{2}Z=21+i3 ohms. Calculate the current in polar form.SolutionTheoryQuestion 19An AC circuit has an impedance Z=3−6iZ=3-6iZ=3−6i ohms and is connected to a voltage source V=90+30iV=90+30iV=90+30i volts. Find the current in both rectangular and polar form.SolutionTheoryQuestion 20Encrypt the word "CODE" by multiplying the complex encryption key k=2−ik=2-ik=2−i. Then decrypt it back to the original word.SolutionTheoryQuestion 21Consider the complex encryption key k=3−3ik=3-3ik=3−3i. Encrypt the word "QUIZ", and then recover the original word using the inverse of the key.SolutionTheoryQuestion 22Encrypt the word "CLASS" by adding the complex encryption key k=−3+4ik=-3+4ik=−3+4i. Then decrypt it back to the original word.SolutionTheory