Solution
Use the mapping A=1,…,Z=26.
Word: CLASS
C=3, L=12, A=1, S=19, S=19
Encryption key (addition):
k=−3+4i
Encryption (add k)
C:L:A:S:S: 3+(−3+4i)=4i 12+(−3+4i)=9+4i 1+(−3+4i)=−2+4i 19+(−3+4i)=16+4i 19+(−3+4i)=16+4i
Encrypted values:
(4i, 9+4i, −2+4i, 16+4i, 16+4i)
Decryption (subtract k)
4i−(−3+4i)(9+4i)−(−3+4i)(−2+4i)−(−3+4i)(16+4i)−(−3+4i)(16+4i)−(−3+4i)=3=12=1=19=19
So the decrypted word is CLASS.
Encrypted: (4i,9+4i,−2+4i,16+4i,16+4i) → Decrypted: CLASS