Solution Given: z1=2(cos60∘+isin60∘),z2=5(cos90∘+isin90∘)z_1=2(\cos 60^\circ+i\sin 60^\circ),\quad z_2=5(\cos 90^\circ+i\sin 90^\circ)z1=2(cos60∘+isin60∘),z2=5(cos90∘+isin90∘) Use: z1z2=r1r2(cos(θ1+θ2)+isin(θ1+θ2))z_1z_2=r_1r_2\left(\cos(\theta_1+\theta_2)+i\sin(\theta_1+\theta_2)\right)z1z2=r1r2(cos(θ1+θ2)+isin(θ1+θ2)) z1z2=(2⋅5)(cos(60∘+90∘)+isin(60∘+90∘))=10(cos150∘+isin150∘)z_1z_2=(2\cdot 5)\left(\cos(60^\circ+90^\circ)+i\sin(60^\circ+90^\circ)\right) =10(\cos 150^\circ+i\sin 150^\circ)z1z2=(2⋅5)(cos(60∘+90∘)+isin(60∘+90∘))=10(cos150∘+isin150∘) cos150∘=−32,sin150∘=12\cos 150^\circ=-\frac{\sqrt{3}}{2},\quad \sin 150^\circ=\frac{1}{2}cos150∘=−23,sin150∘=21 z1z2=10(−32+12i)=−53+5i\boxed{z_1z_2=10\left(-\frac{\sqrt{3}}{2}+\frac{1}{2}i\right)=-5\sqrt{3}+5i}z1z2=10(−23+21i)=−53+5i