Accedmychevron_right11thchevron_rightmathchevron_rightMatrices And Determinantschevron_rightExercise 4.3

Solution

Using Cramer’s rule for AX=BAX=B (with A0|A|\ne 0):

x=AxA,y=AyA,z=AzAx=\frac{|A_x|}{|A|},\qquad y=\frac{|A_y|}{|A|},\qquad z=\frac{|A_z|}{|A|}

(i)

{2x+yz=1xy+2z=33x+2y+z=4\begin{cases} 2x+y-z=1\\ x-y+2z=3\\ 3x+2y+z=4 \end{cases}

Solution:

x=1,  y=0,  z=1\boxed{x=1,\; y=0,\; z=1}

(ii)

{x1+2x23x3=04x1x2+x3=52x1+3x2+2x3=3\begin{cases} x_1+2x_2-3x_3=0\\ 4x_1-x_2+x_3=5\\ -2x_1+3x_2+2x_3=3 \end{cases}

Solution:

x1=6855,  x2=5955,  x3=6255\boxed{x_1=\frac{68}{55},\; x_2=\frac{59}{55},\; x_3=\frac{62}{55}}

(iii)

{2x1x2+x3=1x1+2x2+2x3=2x12x2x3=1\begin{cases} 2x_1-x_2+x_3=1\\ x_1+2x_2+2x_3=2\\ x_1-2x_2-x_3=1 \end{cases}

Solution:

x1=83,  x2=2,  x3=73\boxed{x_1=\frac{8}{3},\; x_2=2,\; x_3=-\frac{7}{3}}