QuestionsQuestion 1Sum the following series upto nnn terms.(i)1×3+2×5+3×7+⋯1 \times 3 + 2 \times 5 + 3 \times 7 + \cdots1×3+2×5+3×7+⋯(ii)1×5+2×8+3×11+⋯1 \times 5 + 2 \times 8 + 3 \times 11 + \cdots1×5+2×8+3×11+⋯(iii)1×2+2×5+3×8+⋯1 \times 2 + 2 \times 5 + 3 \times 8 + \cdots1×2+2×5+3×8+⋯(iv)1×3×5+2×4×6+3×5×7+⋯1 \times 3 \times 5 + 2 \times 4 \times 6 + 3 \times 5 \times 7 + \cdots1×3×5+2×4×6+3×5×7+⋯(v)1×2×4+2×3×7+3×4×10+⋯1 \times 2 \times 4 + 2 \times 3 \times 7 + 3 \times 4 \times 10 + \cdots1×2×4+2×3×7+3×4×10+⋯(vi)22+42+62+⋯2^2 + 4^2 + 6^2 + \cdots22+42+62+⋯(vii)32+62+92+⋯3^2 + 6^2 + 9^2 + \cdots32+62+92+⋯(viii)4×12+7×22+10×32+⋯4 \times 1^2 + 7 \times 2^2 + 10 \times 3^2 + \cdots4×12+7×22+10×32+⋯(ix)3+(3+7)+(3+7+11)+⋯3 + (3+7) + (3+7+11) + \cdots3+(3+7)+(3+7+11)+⋯(x)12+(12+22)+(12+22+32)+⋯1^2 + (1^2 + 2^2) + (1^2 + 2^2 + 3^2) + \cdots12+(12+22)+(12+22+32)+⋯SolutionTheoryQuestion 2Sum the series.(i)12−22+32−42+⋯+(2n−1)2−(2n)21^2 - 2^2 + 3^2 - 4^2 + \cdots + (2n-1)^2 - (2n)^212−22+32−42+⋯+(2n−1)2−(2n)2(ii)121+12+222+12+22+323+⋯\dfrac{1^2}{1} + \dfrac{1^2 + 2^2}{2} + \dfrac{1^2 + 2^2 + 3^2}{3} + \cdots112+212+22+312+22+32+⋯ to nnn termsSolutionTheoryQuestion 3Find the sum to nnn terms of the series whose nthn^{th}nth terms are given.(i)5n2+2n+35n^2 + 2n + 35n2+2n+3(ii)n2+2n−3n^2 + 2n - 3n2+2n−3SolutionTheoryQuestion 4Given nthn^{th}nth terms of the series, find the sum to 2n2n2n terms:(i)3n2+5n+23n^2 + 5n + 23n2+5n+2(ii)n2+n−2n^2 + n - 2n2+n−2SolutionTheory