schoolAccedmy
9th10th
11th12th
school

11TH · MATH

Exercise 6.11

menu_bookSequences (Introduction)menu_bookExercise 6.1menu_bookExercise 6.2menu_bookExercise 6.3menu_bookExercise 6.4menu_bookExercise 6.5menu_bookExercise 6.6menu_bookExercise 6.7menu_bookExercise 6.8menu_bookExercise 6.9menu_bookExercise 6.10menu_bookExercise 6.11
arrow_backBack
school

11TH · MATH

Exercise 6.11

menu_bookSequences (Introduction)menu_bookExercise 6.1menu_bookExercise 6.2menu_bookExercise 6.3menu_bookExercise 6.4menu_bookExercise 6.5menu_bookExercise 6.6menu_bookExercise 6.7menu_bookExercise 6.8menu_bookExercise 6.9menu_bookExercise 6.10menu_bookExercise 6.11
arrow_backBack
Accedmychevron_right11thchevron_rightmathchevron_rightSequences And Serieschevron_rightExercise 6.11

The amount after successive years under compound interest is obtained by multiplying by the constant factor ( \bigl(1 + \frac{r}{100}\bigr) ) each year, which is the definition of a geometric progression.

arrow_back
Previous
Exercise 6.10
On this page
No headings yet